Subject: RE: [xsl] Conditional variable assignment with node-set as value From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Wed, 18 Jul 2001 02:37:54 +0100 |
> I uses Saxon6.0.2 as XSLT processor. Upgrade! The current version is 6.4.3. > I currently have a need to use conditional variable > assignment with node-set as value. I tried to use > saxon:node-set, but still gets the error: I suspect the error is from the way you are using this variable, not from the way you are setting it up. Within this xsl:variable, the two calls on saxon:node-set() seem to be unnecessary: it's never necessary to call saxon:node-set on something that is already a node-set, which both these expressions are. I'm afraid I don't know quite what you mean by conditional variable assigment. Have you considered the syntax: <xsl:variable name="v" select="$ns1[$condition] | $ns2[not($condition)]"/> Mike Kay Software AG > At XSLT 1.0, conversion of a result tree fragment to a > node-set is not allowed. > My XSLT code looks like: > <xsl:variable name="extended-attrs-bid"> > <xsl:choose> > <xsl:when > test="normalize-space(RFQDomainAttributeDefinition)"> > <xsl:value-of > select="saxon:node-set(RFQDomainAttributeDefinition[@Domain > = 'lbid']/ExtendedAttributeDefinition)" /> > </xsl:when> > <xsl:otherwise> > <xsl:value-of > select="saxon:node-set(Bid/ExtendedAttribute[generate-id() > = generate-id(key('extended-attrs-bid-index', > @ExtendedAttributeCode))])" /> > </xsl:otherwise> > </xsl:choose> > </xsl:variable> > How to conditionally assign the node-set value I > needed? > > Much thanks, > Xiaocun > > __________________________________________________ > Do You Yahoo!? > Get personalized email addresses from Yahoo! Mail > http://personal.mail.yahoo.com/ > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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