Subject: RE: [xsl] Getting date of the XSL transformation into HTML output From: Ghostrider <ghostrider@xxxxxxxxxxx> Date: Fri, 20 Jul 2001 12:53:53 +0200 |
Hi Rene (and Lee) [it seems my previous reply didn't make the list for some reason so I'm posting this again] Rene wrote: >I don't quite understand your problem. >The date your XSL is generating the HTML is the current date isn't it? Yes >So why not use one of the suggestions how to get the current date and use the ><xsl:value-of select="the current-date-function of your choice"/> to hardcode it into your HTML? And what would that current-date-function look like? I really have no idea (as to syntax, use,...)! >And if you're using msxml3 (or just IE) and want to know how to pass a >parameter: see my earlier mail: http://www.biglist.com/lists/xsl- >list/archives/200107/msg00002.html I'm using XMLSpy and MSXML3. I had a look at your example code but i don't know 1. where to put in my XSL 2. how to adapt it to so I get the current date in the output HTML As to your reply, Lee: Same problem: how do I use a param to actually get that date? I'd appreciate any help on this (though i didn't think it would be this complicated to get it done). Thanks everyone, Armin XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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