Subject: Re: [xsl] Was test for presence of an attribute From: Goetz Bock <bock@xxxxxxxxxxx> Date: Sat, 21 Jul 2001 21:03:07 +0200 |
On Fri, Jul 20 '01 at 12:39, val iliescu wrote: > How would one go about to print the element names, > followed imediately by their attribute name (if it > exists ?) That's easy: write a template that cataches all nodes (except text nodes) and prints their (local) name, than does a for-each loop over all attributes and print's this names. (And get yourselfe a good book) It goes something along this lines (it produces recoverable errros with saxon for the text nodes): <?xml version="1.0" encoding="UTF-8" standalone="no" ?> <!-- filename: test.xsl created on: 2001 Jul 21 20:48:16 z (CEST) last modified: 2001 Jul 21 21:00:23 z (CEST) (c) 2001 by Goetz Bock <bock@xxxxxxxxxxx> --> <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version='1.0'> <xsl:output method="text" /> <xsl:template match="/"> <xsl:apply-templates /> </xsl:template> <xsl:template match="node()"> <xsl:value-of select="name()" /> <xsl:text>: </xsl:text> <xsl:for-each select="@*"> <xsl:value-of select="name()" /> </xsl:for-each> <xsl:text> </xsl:text> <xsl:apply-templates /> </xsl:template> <xsl:template match="text()" /> </xsl:transform> -- Goetz Bock IT Consultant Dipl.-Inf. Univ.
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