Subject: Re: [xsl] Re: Réf.[2]_:_Réf.[2]_:_Transforming_non_structured_XML_into structured XML with XSLT From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Thu, 9 Aug 2001 06:29:23 -0700 (PDT) |
> While this works for the first level, it does not for the seccond, or > how would you represent my full example above: > > <row folder1="ROOT" folder2="f1"/> > <row folder1="f1" folder2="f2"/> > <row folder1="f2" folder2="f3"/> > <row folder1="f3" folder2="f4"/> > <row folder1="ROOT" folder2="f2"/> > <row folder1="f2" folder2="f4"/> > > could also describe: > > / > +- f1 > | `- f2 > | +- f3 > | | `- f4 > | `- f4 > `- f2 > No, not if there's the convention that the order of "row" elements is according to a depth-first traversal. In this case your last example will be represented as: <row folder1="ROOT" folder2="f1"/> <row folder1="f1" folder2="f2"/> <row folder1="f2" folder2="f3"/> <row folder1="f3" folder2="f4"/> <row folder1="f2" folder2="f4"/> <row folder1="ROOT" folder2="f2"/> I agree that this is getting off-topic. Cheers, Dimitre Novatchev. __________________________________________________ Do You Yahoo!? Make international calls for as low as $.04/minute with Yahoo! Messenger http://phonecard.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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