RE: [xsl] How can I find a particluar element in an XML file?

["Sunil Dua" <sdua@xxxxxxxxxxxxxxx>]

try this


          		<xsl:apply-templates
select="/table/row/column[@name='personID']/." />

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Phil
Sent: Wednesday, August 22, 2001 9:05 AM
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] How can I find a particluar element in an XML file?




 I am trying extract a particular data item and so far have been unable to
find out how to do it, any help would be much appreciated.

Below is an extract of my  input XML file :

<?xml version="1.0"?>
<table name="Industry">
	<row command="update">
		<column name="Periodical">No</column>
		<column name="personID">ML101363</column>
		<column name="PersonNumber">449.0773</column>
	</row>
</table>

I want to be able to grab the value of 'personID' (In this case ML101363),
my problem is that do not know how to specifically request personID, is
there a 'where' clause or something similar I can use?

This is how I would like my XML output file to appear.

< PRODUCT >
	<PersonID>ML101363</PersonID>
</ PRODUCT >



The XSL below simply selects al the columns but how can I request a specific
column name. Any help much appreciated.

<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output method="xml"/>

<xsl:template match="/">
	<PRODUCT>
          		<xsl:apply-templates select="/table/row/column" />
	</PRODUCT>
</xsl:template>


<xsl:template match="column">
	<PersonID>
     <xsl:value-of select="."/>
	</ PersonID >
</xsl:template>

</xsl:stylesheet>





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