RE: [xsl] Removing nodes that have duplicate names

[Phil Servedio <pservedio@xxxxxxxxxxxxxx>]

Thanks Tom!

-----Original Message-----
From: Thomas B. Passin [mailto:tpassin@xxxxxxxxxxxx]
Sent: Wednesday, August 22, 2001 1:27 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Removing nodes that have duplicate names


<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match='/'>
<xsl:apply-templates/>
</xsl:template>

<!--=== Make a slight change to this line ===-->
<xsl:template match='/root/dupnode'/>

<xsl:template match='@* | node()'>
<xsl:copy>
<xsl:apply-templates select='@* | node()'/>
</xsl:copy>
</xsl:template>

</xsl:stylesheet>


Cheers,

Tom P

[Phil Servedio]

> I have an xml tree which looks like the following. I want
> to copy the source tree to a result tree minus certain
> nodes. However some node names are duplicated:
>
> ...
> This xsl removes all <dupnode>s. How do I remove
> only the <dupnode> at the root?
>
> Can a template directive say 'match <this> andparent node = root'?
>



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