RE: [xsl] XPath position determination

Subject: RE: [xsl] XPath position determination
From: Jarno.Elovirta@xxxxxxxxx
Date: Fri, 31 Aug 2001 10:46:05 +0300
> <root>
> <item>A</item>
> <item>B</item>
> <item>C</item>
> </root>
> 
> using XPath what is the simplest way to determine the 
> position/index of B relative to the root?
> 
> So "/root/item[.='B']" gets me to it and 
> "/root/item[position()=1]" does also,

That would actually select the A item.

> but how do i get the 
> position back for any element?

When your current node is one of the items, "count(preceding-sibling::item)
+ 1" will give you the "position" of that item.

Jarno




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