RE: [xsl] How to output attribute without namespace

Subject: RE: [xsl] How to output attribute without namespace
From: Dmitri Ilyin <dmitri.ilyin@xxxxxxxxx>
Date: Fri, 7 Sep 2001 09:58:38 +0200
Thanks David.
It works.But the problem that i have is i don't know the local-name of
attribute....

> -----Original Message-----
> From: David Carlisle [mailto:davidc@xxxxxxxxx]
> Sent: Thursday, September 06, 2001 7:14 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] How to output attribute without namespace
> 
> 
> 
> take the identity transform from the xsl spec and add one 
> extra template
> 
> <xsl:template match="@param:height" 
> xmlns:param="http://localhost/testui.txt";>
> <xsl:attribute name="param"><xsl:value-of select="."/></xsl:attribute>
> </xsl:template>
> 
> then you are done.
> 
> David
> 
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