Subject: [xsl] passing parameters to an import file From: "Tanzila Mohammad" <tmohammad@xxxxxxxxxxxxxxxxxxxx> Date: Mon, 10 Sep 2001 12:18:41 +0100 |
I have a xsl stylesheet (main.xsl) which imports another xsl stylesheet (common.xsl). Within main.xsl there is the following code: <xsl:call-template name="noResults"/> <!--noResults is contained within the common.xsl--> However, common.xsl requires a parameter which is utilized by the noResults template, is there a way to pass the parameter to the template from main.xsl via the call? Something like this: <xsl:call-template name="noResults(<xsl:value-of select="$param"/>)"/> Thanks Tanzila XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] XQuery 1.0 and XPath 2.0 , DPawson | Thread | Re: [xsl] passing parameters to an , cutlass |
[xsl] html to xsl........, Vadiraj | Date | Re: [xsl] passing parameters to an , cutlass |
Month |