RE: [xsl] outputing a non existant element.

Subject: RE: [xsl] outputing a non existant element.
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Wed, 12 Sep 2001 20:54:31 +0100
> i have one optional element in my schema-file say:
> <fruit>orange</fruit>.The default value of fruit is
> "apple".I would like to have a xslt-transformation
> which gives me the content of the fruit element if it
> appears in the xml-file or its default value if it
> doesn't appear.

The simple answer is
<xsl:choose>
<xsl:when test="fruit"><xsl:value-of select="fruit"/></xsl:when>
<xsl:otherwise>apple</xsl:otherwise>
</xsl:choose>

If you prefer brevity to clarity, you can write
<xsl:value-of select="concat(fruit, substring('apple', 1, not(fruit)*5)

Mike Kay

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread