Subject: RE: [xsl] grouping problem From: "Corey Spitzer" <cspitzer@xxxxxxxxx> Date: Thu, 20 Sep 2001 09:38:35 -0500 |
assuming your input cid's are in alphabetic or numeric order... this should work: <xsl:for-each select="//concept[not(following::concept[1]/@cid=@cid)]"> <xsl:value-of select="@cid"/> </xsl:for-each> I would expect what you have already would work, but I think this is a little bit more definite.. I don't know, but it's worth a try. -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of thomas george Sent: Thursday, September 20, 2001 9:11 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] grouping problem Hi Folks, I am just trying to get the unique values of an attribute and just not getting it. I had succcess in getting the unique values for elements with the same expression.Am i missing something or is there a different way to get the unique values for attributes <xsl:for-each select="//conept/@cid[not(. = following::concept/@cid)]"> <xsl:value-of select="."/> </xsl:for-each> The above statement doesnot give me the unique values of the @cid attribute. Thanks Thomas __________________________________________________ Terrorist Attacks on U.S. - How can you help? Donate cash, emergency relief information http://dailynews.yahoo.com/fc/US/Emergency_Information/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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