Subject: [xsl] Grouping nodes by 4 using "(position() mod 4)*100" From: "Brad Crouch" <brad@xxxxxxxxxxxxxx> Date: Thu, 27 Sep 2001 13:25:58 +0930 |
I would like to display n amounts of nodes in a for-each and group them by 4's ie 12 menu items witha repeating pattern every 4 menu items. Looking in the MSXML documentation I came up with the following XSL: <xsl:if test="(position() mod 4)*100 = 0"> <p>remainder = 0</p> </xsl:if> <xsl:if test="(position() mod 4)*100 = 25"> <p>remainder = .25</p> </xsl:if> <xsl:if test="(position() mod 4)*100 = 50"> <p>remainder = .5</p> </xsl:if> <xsl:if test="(position() mod 4)*100 = 75"> <p>remainder = .75</p> </xsl:if> Which I could extend to do what I need. However when I ran it I got the following error MSXML3.DLL error '80004005' Unknown method. -->position()<-- mod 4*100 = 0 Which indicates the position function is not available... Is there somewhere I need to do some sort of include etc.. to have this function available? Thanks in advance, Brad Crouch XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] Checking the text nodes j, Adam Van Den Hoven | Thread | RE: [xsl] Grouping nodes by 4 using, Michael Kay |
[xsl] Checking the text nodes just , Adam Van Den Hoven | Date | RE: [xsl] Checking the text nodes j, Jarno . Elovirta |
Month |