RE: [xsl] questions.

Subject: RE: [xsl] questions.
From: "Mihir D. Gore" <mihirg@xxxxxxxxxxxxxxxxxxxxx>
Date: Thu, 4 Oct 2001 14:32:16 +0530
but if want to replace node b with node z ie

<a>
	<b>
		<c></c>
	</b>
</a>

is changed to
<a>
	<x>
		<c></c>
		<m></m>
		<n></n>
	<x>
</a>

I can achive this by simply deleting node b and its chilren and adding node
x.
Is there any other way around this?

mihir
-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Manu KY
Sent: Thursday, October 04, 2001 2:09 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] questions.


Hi,
write xsl:template match = "b"

Manu
>hi,
>I have a xml file in the form
>
><a>
>         <b>
>                 <c></c>
>         </b>
></a>
>
>I want to add two more children to node b say  m and n so that the
resultant
>xml looks like this.....
>
><a>
>         <b>
>                 <c></c>
>                 <m></m>
>                 <n></n>
>         </b>
></a>
>
>BUT in the xsl file in want to specify the path with respect to node b.
>How do i do it?
>mihir
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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