Re: [xsl] Reformatting character strings

There are much solutions in FAQ and in the list archives. Use substring().

Joerg

Burisch, Curtis wrote:

Hi,

As ususal, I'm sorry if this is in the faq but could someone give me a
pointer on how I can reformat a date (it's in an attribute) from DD/MM/YYYY
format to MM/DD/YY format?

Thanks,
Curtis.

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[xsl] Reformatting character strings Burisch, Curtis - Fri, 16 Nov 2001 15:30:52 -0000 cutlass - Fri, 16 Nov 2001 15:43:33 -0000 Michael Kay - Fri, 16 Nov 2001 16:37:11 -0000 Jörg Heinicke - Fri, 16 Nov 2001 19:23:38 +0100 <= <Possible follow-ups> Burisch, Curtis - Fri, 16 Nov 2001 15:52:47 -0000

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