Subject: RE: [xsl] select all nodes WITHOUT a specific attribute? From: Nisheet Verma <NisheetV@xxxxxxxxxxx> Date: Mon, 3 Dec 2001 12:20:27 -0800 |
try <xsl:for-each select="things/thing[not(@id!='')]"> It works. I don't know why I would need not() here but <xsl:for-each select="things/thing[@id='']"> does not work hence reversed the logic and introduced not() and it works. Nisheet -----Original Message----- From: William Bagby [mailto:williamb@xxxxxxxxx] Sent: Monday, December 03, 2001 11:42 AM To: XSL Mailing List (E-mail) Subject: [xsl] select all nodes WITHOUT a specific attribute? How do I select all nodes that DO NOT have a specific attribute? For example, I have <things> <thing id="1">One</thing> <thing>shoe</thing> <thing>bear</thing> <thing id="2">Two</thing> <thing id="3">Three</thing> <thing>airplane</thing> <thing id="4">Four</thing> <thing id="5">Five</thing> </things> and I want: <thing>shoe</thing> <thing>bear</thing> <thing>airplane</thing> What I got so far is <xsl:for-each select="things/thing[string-length(@id) = 0]"> ... </xsl:for-each> This seems to work, but it rubs me the wrong way. Is there a more elegant solution? William Bagby XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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