RE: [xsl] How to express a select attr in for-each for conditional or nonconditonal case.

["Chris Bayes" <chris@xxxxxxxxxxx>]

I see.
Ok you want
<xsl:for-each select="$source[contains($keywrd,.)]|$source[$keywrd='']">


Ciao Chris

XML/XSL Portal
http://www.bayes.co.uk/xml


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> E100 SFYang
> Sent: 20 December 2001 03:35
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] How to express a select attr in for-each for 
> conditional or nonconditonal case.
> 
> 
> Hi, listers,
> 
> I use contains function to get the selected item defined
> by select attr of param element. such as;
> 
> <xsl:for-each select="$source[contains($keywrd,.)]">
> 
> Of course using this expression for empty param, nothing will 
> be displayed.
> 
> I wonder how to modify the above select att to be able to display
> 
>  1. selected items when keywrd is not empty.
>  2. all items when keywrd is empty.  
> 
> Thanks for any help in advance.
> 
> Sun-fu Yang
> 
> sfyang@xxxxxxxxxxxxx
> 
> ***  simplified xml file  **
> <?xml-stylesheet href="test.xsl" type="text/xsl"?>
> <docs>
> <item>a</item>
> <item>b</item>
> <item>c</item>
> </docs>
> 
> 
> ***   xsl   file  **
> <?xml version='1.0'?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> version="1.0">
> <xsl:key name="sourcekey" match="item" use="."/>
> <xsl:variable name="source" 
> select="/docs/item[generate-id(.)=generate-id(key('sourcekey',
> .)[1])]"/>
> <xsl:param name="keywrd" select="'a,b'"/>
> <xsl:template match="/">
> 
> <xsl:for-each select="$source[contains($keywrd,.)]">
> <xsl:value-of select="."/>
> </xsl:for-each>
> </xsl:template>
> </xsl:stylesheet>
> 
> 
> 
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> 
> 


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