Subject: Re: [xsl] Re: The Solution -- Re: how to rearrange nodes based on a dependency graph? From: Joerg Pietschmann <joerg.pietschmann@xxxxxx> Date: Thu, 03 Jan 2002 16:26:04 +0100 |
> - --- Gunther Schadow <gunther@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > As beautifully as this is designed, the only sad thing is that > > it can't work without using some Microsoft (or other) extension. There is a XSLT code for topological sort available which doesn't rely on xx:node-set(), last seen at http://www.dpawson.co.uk/xsl/sect2/N6461.html#d195e853 Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote: > It is true, that without the xx:node-set() function, XSLT 1.0 is 50% > crippled. Well, that's somewhat bold. I was able to get rid of xx:node-set() i most cases i was tempted to use it, by sacrificing readability. I agree that abandoning RTFs is a good idea in general, but variables holding constructed node sets have it's own set of pitfalls attached, and we'll see a lot of abuse of this feature once it is the standard. Regards J.Pietschmann XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] remaining problem w/ dyn , Matt G. | Thread | [xsl] UTF-8 html output and links, Casadome, Francisco |
[xsl] XSL, SSL, IE, and Caching, Evan Child | Date | RE: [xsl] Wishes for XSL revisions , Joerg Pietschmann |
Month |