RE: [xsl] XPath expression to derive list of distinct element names

["Michael Kay" <michael.h.kay@xxxxxxxxxxxx>]

I don't think it can be done in XPath 1.0. The "implicit existential equals" in XPath works only on node-sets, so it's only useful for eliminating nodes that have duplicate string-values, not duplicate values of some other function such as name().

Mike Kay 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of 
> Sean McMurray
> Sent: 09 January 2002 19:48
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] XPath expression to derive list of distinct 
> element names
> 
> 
> I need an XPath expression that will return a list of node 
> names it the 
> tree frag.
> I want the names to be distinct.
> 
> The best I can come up with is:
>     "*[local-name() != local-name(preceding-sibling::*)]"
> 
> But the local-name function only gives the name of the first 
> node in the 
> nodeset.
> 
> This is really an XPath question. I'm not doing this in XSL, 
> so I can't 
> use templates or any other non-XPath construct.
> It needs to be a single XPath expression.
> 
> Thanks for any help.
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list