Subject: Re: [xsl] need xpath From: "Joerg Heinicke" <joerg.heinicke@xxxxxx> Date: Thu, 31 Jan 2002 11:59:32 +0100 |
Hello Andrew, the would be the id()-function, but you need to have a DTD than, which sets your id-attribute to ID: <xsl:template match="xref"> <xsl:value-of select="id(@xrefid)/@label"/> </xsl:template> The second best method is using keys (possible without DTD): <xsl:key name="graphics" match="graphic" use="@id"/> <xsl:template match="xref"> <xsl:value-of select="key('graphics',@xrefid)/@label"/> </xsl:template> Regards, Joerg ----- Original Message ----- From: "Andrew Welch" <andrew@xxxxxxxxxxxxxxxxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Thursday, January 31, 2002 11:42 AM Subject: [xsl] need xpath > > I have the line: > > <graphic id="XBWQEF00F" boardno="N0011939.FAX" size="A4" rfa="(Pre > Mod.02138)" label="2" inschlvl="3" mark="1"/> > > And the line: > > <xref xrefid="XBWQEF00F"/> > > When I encounter the <xref> element I want to output the 'label' attribute > >from the corresponding graphic element. > > Any ideas? > > Cheers > > andrew XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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