Re: [xsl] sort and if

["Joerg Heinicke" <joerg.heinicke@xxxxxx>]

Just use a grouping technique like Muenchian Method, which was discussed on
this list today in about 20 messages.

The problem with your method is the following:

<xsl:for-each select="item">
    <xsl:sort select="date"/>
    <xsl:if test="preceding-sibling::item[1][date= current()/date]">
        <xsl:value-of select="date"/>
    </xsl:if>
</xsl:for-each>

The test on preceding <item> elements sounds very good, but it's using the
document order and not the sorted order.

Regards,

Joerg

----- Original Message -----
From: "Ilyasov Jienbay" <jienbay@xxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, February 05, 2002 1:00 PM
Subject: [xsl] sort and if


> hello,
>
> please help with this...
> it drives me crazy!
>
> <items>
> <item>
> <date>011022<date>
> </item>
> <item>
> <date>011021<date>
> </item>
> <item>
> <date>011021<date>
> </item>
> </items>
>
> i want to *sort* and then put "same as above" or *nothing* if the
previouse
> $date is equal to the current $cur_date, something like:
>
> date
> -----
> 011021
> same as above(or nothing)
> 011022
>
> thank you in advance
>
> jian


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