Subject: [xsl] value of xsl:param in xsl:sort From: "Kunal H. Parikh" <kunal@xxxxxxxxxx> Date: Thu, 14 Feb 2002 15:41:05 +1100 |
Hi ! ======================== <xsl:param name="sortByElement">AuthorList/Author/Name</xsl:param> <xsl:sort select="$sortByElement" order="ascending"></xsl:sort> ======================== The above code does not seem to be replacing the $sortByElement for the parameter. But, if I replace "$sortByElement" with "AuthorList/Author/Name", everything works out just fine. Can someone please suggest what mistake I am making ? TIA, Kunal XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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