Subject: Re: [xsl] position of non actual element From: "Rudolf Pischek" <rudolf.pischek@xxxxxxx> Date: Thu, 28 Feb 2002 07:45:32 +0100 |
Hi oliviere, >position() returns always the position of the current node within the >context node list. There's nothing like a "global position". I know :-)) >So, what do you mean by "position"? ok, my original data are: <table> <cols> <col name="persno" width="..." align=".." grid="..." .....> <col name="name" width="..." align=".." grid="..." .....> <col name="address" width="..." align=".." grid="..." .....> </cols> <rows> <row memo=".."> <cell>123</cell> <cell>John Smith</cell> <cell>1st avenue, 1040 Boston</cell> </row> ... </rows> </table> When I format this xml I want: <xsl:for-each select="table/rows/row"> <TR><TD><xsl:value-of select="give me the cell which position is the same as the position of element col which attribute is name"/> </TD> </TR> </xsl:for-each> Thats all what I want. I think if you write select="element[position() = 5]" that means that parser must find position of "element", why I cannot know the number of this position(), why only in test? Rudolf Pischek XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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