Subject: [xsl] Contains(@href. '/') returns false From: "NILESH PATEL" <jayganesh786@xxxxxxxxxxx> Date: Fri, 08 Mar 2002 11:31:44 +0000 |
********** test.xsl ********* <?xml version="1.0" encoding="UTF-8" ?>
<!-- Document : real_partitions.xsl Created on : 27 February 2002 Author : npatel Comment purpose of transformation follows. -->
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:template name="lastIndexOf"> <!-- declare that it takes two parameters - the string and the char --> <xsl:param name="string" /> <xsl:param name="char" /> <xsl:choose> <!-- if the string contains the character... --> <xsl:when test="contains($string, $char)"> <!-- call the template recursively... --> <xsl:call-template name="lastIndexOf"> <!-- with the string being the string after the character --> <xsl:with-param name="string" select="substring-after($string, $char)" /> <!-- and the character being the same as before --> <xsl:with-param name="char" select="$char" /> </xsl:call-template>
<!--xsl:value-of select="$string" /--> </xsl:template>
<xsl:template match="test"> <html> <head> <title>Test of Strings</title> </head> <body> <xsl:for-each select="test_string"> <xsl:variable name="file"> <xsl:call-template name="lastIndexOf"> <xsl:with-param name="string" select="substring-before(@href, '#')" /> <xsl:with-param name="char" select="/" /> </xsl:call-template>
</xsl:variable> <xsl:value-of select="$file"/>
</xsl:for-each> </body> </html> </xsl:template>
************* test.html ************* <html xmlns:fo="http://www.w3.org/1999/XSL/Format"> <head> <title>Test of Strings</title> </head> <body>h:/rcs/product/src/software/xml/pml/unit_tests/xml_data/storage.xml
</body> </html>
Following the syntax I should get only <body>storage.xml</body> in output.
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