Re: [xsl] xsl:sort by element name

["Andrew Welch" <awelch@xxxxxxxxxxxxxxx>]

> 
> Dear List,
> I am trying to sort my output nodes based on their element name.
> 

Mike,

This will sort all children of <root> by their name()

==xml==
<root>
  <a>x</a>
  <c>x</c>
  <b>x      
          <d>x</d>
  </b>
  <z>x</z>
  <g>x</g>
</root>

==output==
<a /><b /><c /><d /><g /><z />

==xsl==
<xsl:template match="/">
  <xsl:apply-templates select="root//*">
    <xsl:sort select="name()"/>
  </xsl:apply-templates>
</xsl:template>

<xsl:template match="*">
  <xsl:copy/>
</xsl:template>

cheers
andrew













> 
> Dear List,
> I am trying to sort my output nodes based on their element name.
> 
> Could someone give me a hint on this one?
> 
> Mike F.
> 
> 
> XML:
> <LLL>
>   <C1012>...C-data...</C1012>
>   <C1012>...A-data...</C1012>
>   <C1012>...B-data...</C1012>
> </LLL>
> 
> Output should be:
> <LLL>
>   <C1012>...A-data...</C1012>
>   <CC1012>...B-data...</CC1012>
>   <CCC1012>...C-data...</CCC1012>
> </LLL>
> 
> 
> XSL:
> <xsl:template select="/">
>   <xsl:for-each select="/*">
>     <xsl:sort select="name()"/>
>       <xsl:apply-templates select="C1012"/>
>   </xsl:for-each>
> </xsl:template>
> 
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