Subject: Re: [xsl] combine xml files From: Ming <myu@xxxxxxxx> Date: Wed, 10 Apr 2002 16:45:28 -0600 |
Hi, Tom, To make my explanation easier to understand (sorry for the misleading), I'm going to describe my task. Actually I'm doing the "View Marked" function after a search. The saved searched are saved in a temporary file with the session id as the file name. And each entry in the file is a complete path to a xml file. So, the number of xml files saved in the temporary file can vary from 1 to 1000. After the user click on the view marked button, I need to display the title and author information for each xml file to the user. So, it's a dynamic process. For the title in each xml file, the title format for each database is slightly different and so are others such as author. That's why we have a preference list for titles, authors, etc because different group of people prefer different display format for titles, authors, etc. Yes, I need to look through each xml record since some titles appears only in one database and some appear in more than one database. So, the <db*> tags are different. And I need to find out the most preferred one to display from my preferrence list. Is that possible that in my stylesheet, I call a java function with the path to xml record and parse the xml record in the java function and return the preferred db for each entry? For example, <xsl:value-of select="/xml/*[name()=dbPref:getTitleDbPref($xmlFileName)]/title" /> Will this be too slow to do? Thanks a lot. Ming "Thomas B. Passin" wrote: > [Ming] > > > > Thanks a lot for your help and this is really helpful. But after starting > > thinking about the details, I found my problem is more complicate than > I've > > thought. > > > > The individual xml file is actually more complicate. We have more > databases and > > each record can appear in multiple databases. So, the xml file is actually > in > > this format: > > > > <xml> > > <db1> > > <title db=db1> title in db1 </title> > > <authors> > > <author db=db1> author name in db1 </author> > > <author db=db1> author name in db1 </author> > > </authors> > > </db1> > > <db2> > > <title db=db2> title in db2 </title> > > <authors> > > <author db=db2> author name in db2 </author> > > <author db=db2> author name in db2 </author> > > </authors> > > </db2> > > </xml> > > > > And I have a preference which contains the preferred database order for > title > > display, author display and so on. For example, title display's database > > preference is "db2 db1". What I need to do is to loop through the > preferred > > list and find the title in that database. > > > > I don't understand your problem enough to make suggestions. Is there one > xml file per work? If not, and if the title can be different in db1, db2, > etc., how can you know which block of data applies to the same work? Do you > want to process all the files at once with the same db preferences? Do you > have to look across multiple xml files to find the various entries for db1, > db2, etc. that apply to the same work? > > Depending on the details of your task, it may be best to make two passes > through the files, but that remains to be seen > > Cheers, > > Tom P > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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