Subject: RE: [xsl] DTD From: "Dion Houston" <dionh@xxxxxxxxxxxxx> Date: Wed, 1 May 2002 02:59:10 -0700 |
Hi Tinku: (anyone else on the list please correct me if I'm wrong) XSLT doesn't do anything at all with DTD's other than to allow you to specify one on an output file. In the case of a DTD present in an XML file, XSLT won't see it, and therefore has no ability to copy it (not to mention, XSLT works with source _xml_ files, not DTD) In the case of default value, entities, etc, the DOM (or underlying document model) expands out the values. Therefore if you have a default value of "default" for an attribute "bar" on element "foo", XSLT sees <foo bar="default"/> If your source contains: <foo/> And if you do a copy of that element, your output will be: <foo bar="default"/> HTH! Dion -----Original Message----- From: tinku [mailto:amegha1@xxxxxxxxxxxxxx] Sent: Wednesday, May 01, 2002 2:33 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] DTD hi, Does XSLT processor modifies the DTD present in the original input file? How does the XSLT processor restores the default values present in the DTD in the input file? ------- Tinku _________________________________________________________ Click below to visit monsterindia.com and review jobs in India or Abroad http://monsterindia.rediff.com/jobs XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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