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Re: [xsl] Transformation in NetScape 6.2 Browser

Subject: Re: [xsl] Transformation in NetScape 6.2 Browser
From: "Roma Yankin" <polfin@xxxxxxxx>
Date: Wed, 8 May 2002 23:58:31 +0400
Hi Pundalik,

Actually there is no difference in transforming xml documents both for IE6
and NS6. However you might be using transformNode() method from JS which is
implemented only in IEs with MSXML 3 and higher installed.
Anyway check out this code that makes simplest trasformation of an xml tree.

XML file:
~~~~~~~~~~~~~~~~~~~~~~~~~~~
<?xml-stylesheet type="text/xsl" href="xsl.xsl"?>
<sample>
  <hasattrib hasit="true">
    I have attribute
  </hasattrib>
  <ihave hasit="candy">
    I have attribute
  </ihave>
  <noattribute>
    Nothing here
  </noattribute>
  <mychildhave>
    <child hasit="toy"/>
  </mychildhave>
</sample>

XSL file:
~~~~~~~~~~~~~~~~~~~~~~~~~~~

<xsl:stylesheet
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
 version="1.0">
 <xsl:output method="html"/>
  <xsl:template match="/">
   <html>
    <body>
     <xsl:for-each select=".//*">
      <xsl:if test="@hasit">
        <b><xsl:value-of select="name()"/></b> have "hasit" attribute set to
        <b><xsl:value-of select="@hasit"/></b> <br/>
      </xsl:if>
     </xsl:for-each>
    </body>
   </html>
  </xsl:template>
</xsl:stylesheet>

This will work both in IE and NS,

----
regards Roman!




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