Subject: Re: [xsl] Adjusting sorted list From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Thu, 16 May 2002 16:35:55 +0100 |
Andrew Timberlake wrote: > I have the following XML: > <a> > <b>4</b> > <b>9</b> > <b>6</b> > <b>1</b> > <b>8</b> > <b>6</b> > <b>4</b> > <b>7</b> > </a> > > I am trying to generate the following ouput: > <a> > <b rank="1">1</b> > <b rank="2">4</b> > <b rank="2">4</b> > <b rank="3">6</b> > <b rank="3">6</b> > <b rank="4">7</b> > <b rank="5">8</b> > <b rank="6">9</b> > </a> For interest, the XSLT 2.0 version would be: <xsl:template match="a"> <a> <xsl:for-each-group select="b" group-by="." /> <xsl:sort select="." /> <xsl:variable name="rank" select="position()" /> <xsl:for-each select="current-group()"> <b rank="{$rank}"> <xsl:value-of select="." /> </b> </xsl:for-each> </xsl:for-each-group> </a> </xsl:template> Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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