Subject: [xsl] <xsl:for-each select question From: "dmitri kerievsky" <dmitrik@xxxxxxxxxxxxxx> Date: Fri, 17 May 2002 22:20:01 -0400 |
any idea how order-by would be incorporated into the "for each select" line ? <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:saxon="http://icl.com/saxon" version="1.0"> <!-- Test exslt:distinct --> <xsl:template match="/"> <SELECT name="paglassociates/pagl/state"> <out> <distinct-states>: <xsl:for-each select="saxon:distinct(//paglassociates/pagl/state)"> <OPTION> <!-- <xsl:attribute name="value"><xsl:value-of select="@id"/></xsl:attribute> <xsl:value-of select="@name"/> <xsl:attribute name="value"><xsl:value-of select="@state"/></xsl:attribute> --> <xsl:value-of select="."/> </OPTION> </xsl:for-each> </distinct-states> </out> </SELECT> </xsl:template> </xsl:stylesheet> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Search and replace many strin, Zack Brown | Thread | RE: [xsl] <xsl:for-each select ques, Stuart Celarier |
[xsl] Search and replace many strin, Zack Brown | Date | [xsl] replacing < > in template, Mattias Konradsson |
Month |