Subject: Re: [xsl] creating list from structured paragraphs From: "Roma Yankin" <polfin@xxxxxxxx> Date: Mon, 20 May 2002 10:23:01 +0400 |
Hi David, This XSL transformation outputs exactly the same code as you need using native XML It uses two templates, 1st matchs <doc> and <para> elements, and the second transforms all <para-1> into <list-item> simultaneously pasting text part. XML ---------------------------------------------------- <?xml-stylesheet type="text/xsl" href="xsl.xsl"?> <doc> <para>The following text is a list <para-1>List item No. 1</para-1> <para-1>List item No. 2</para-1> <para-1>List item No. 3</para-1> </para> </doc> XSL ---------------------------------------------------- <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml"/> <xsl:template match="/"> <doc> <par> <xsl:value-of select="par"/> <xsl:apply-templates/> </par> </doc> </xsl:template> <xsl:template match="para-1"> <list-item><xsl:value-of select="."/></list-item> </xsl:template> </xsl:stylesheet> ----- Regards, Roman XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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