Re: [xsl] accessing last element of node set passed as parameter

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

Hello Paul,

you're again creating a RTF and must convert it to a node-set. Either in 
your "A" template or by changing the apply-templates again:

<xsl:variable name="tmp">
  <xsl:copy-of select="$result"/>
  <BAR i="{$i}"/>
</xsl:variable>
<xsl:apply-templates select="following-sibling::*[1]">
  <xsl:with-param name="result" select="xalan:nodeset($tmp)"/>
</xsl:apply-templates>

Regards,

Joerg

paul morgan schrieb:
> Thanks David!  Some of this is starting to click ... but then again something happens that shuts the clicker down.
>
> Since order is important to me, I decided to heed your warning about the ordering of a union being implementation dependent, so I set about making all of the "BAR" elements be siblings of one another.  I replaced:
>
>     <xsl:apply-templates select="following-sibling::*[1]">
>         <xsl:with-param name="result" select="$result|xalan:nodeset($new)"/>
>     </xsl:apply-templates> </xsl:template> 
>
> with:
>
>     <xsl:apply-templates select="following-sibling::*[1]">
>         <xsl:with-param name="result">
>             <xsl:copy-of select="$result"/>
>             <BAR i="{$i}"/>
>         </xsl:with-param>
>     </xsl:apply-templates> </xsl:template> 
>
> but now I get the following error message:
>
>     Can not convert #RTREEFRAG to a NodeList!
>
> at the line:
>
>     <xsl:copy-of select="($result/BAR)[last()]" />
>
> the first time the "A" template is matched with a non-empty value for "result".  Shouldn't "result" be a node set?
>
> Paul (I think this language is going to make my head explode)


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