Subject: Re: [xsl] Parsing a List From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Tue, 21 May 2002 22:00:11 +0200 |
<xsl:param name="first" select="1"/> <xsl:param name="count" select="50"/>
> <xsl:template match="DATALIST"> > <table cellpadding="5" cellspacing="0" border="0"> > <tr> > <td width="135"><u><font color="green">Company</font></u></td> > <td width="330"><u><font color="green">Address </font></u></td> > <td width="100"><u><font color="green">Phone </font></u></td> > <td width="100"></td> > </tr> > <xsl:apply-templates select="customer"/>
> </table> > </xsl:template>
<xsl:template match="customer">
<tr> <td valign="top"><a><xsl:attribute name="href"> adminViewCompanyByID?companyid=<xsl:value-of select="id"/>&companyname =<xsl:value-of select="invoicename"/></xsl:attribute><xsl:value-of select=" invoicename"/></a></td> <td valign="top"><xsl:value-of select="invoiceaddress"/></td> <td valign="top"><xsl:value-of select="phone"/></td> </tr> </xsl:template>
Simply, all this code does is displays all customers contained in the database. However my problem is that I have 1000s of customers in the database and as a result all these are returned in one huge list. My web page is therefore ridicously wrong.
Does anyone know anyway of displaying say 50 Customers at a time with a 'next' and "previous" link to display the next or previous 50.
Any help would be greatly appreciated.
Thanks - ken
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