Re: [xsl] Grouping duplicate elements under one element

["J.Pietschmann" <j3322ptm@xxxxxxxx>]

Uslu, Cihan Y (MED) wrote:
> Hi,
> I have the following XML fragment, and I want to group duplicate course
> elements under one course element. WHat is the best way of doing it? 
> Cihan
It's again the old trusty spell named Muenchean grouping, just
invoked three times in the last few hours.

 <xsl:key name="course" match="course" use="LOCAL_CRSE_CD"/>
 <xsl:template match="courses">
  <courses>
   <xsl:for-each select="course[generate-id()=
      generate-id(key('course',LOCAL_CRSE_CD)[1])]">
     <course>
       <xsl:copy-of select="LOCAL_CRSE_CD"/>
       <xsl:for-each select="key('course',LOCAL_CRSE_CD)">
         <xsl:copy-of select="*[not(self::LOCAL_CRSE_CD)]"/>
       </xsl:for-each>
     </course>
    </xsl:for-each>
  </courses>
 </xsl:template>

Beware, untested.

J.Pietschmann


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