Re: [xsl] Finding node having maximum value for an attribute

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

<xsl:template match="Archives">
  <xsl:value-of select="Archive[not(@ID &lt; 
preceding-sibling::Archive/@ID)]/@ID"/>
</xsl:template>

Joerg

Bagchi Ratul wrote:
> Hi,
> I have a XML which has the following structure :
> <Archives>
> <Archive ID="1">
> <somenode>somevalue</somenode>
> <someothernode>someothervalue</someothernode>
> </Archive>
> <Archive ID="2">
> <somenode>somevalue</somenode>
> <someothernode>someothervalue</someothernode>
> </Archive>
> </Archives>
>
> Now my question is, is it possible to wite a XPath query which will return
> me the highest ID attribute if Archive node in the whole file???
>  
> Regards,
> Ratul.


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