Re: [xsl] generate-id() question

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

nrashidi wrote:
> Novice question...
> I need to create links and i need the output of template match T to correspond 
> to the ID values that are used in the href. I am not sure what needs to be put 
> for the node-set argument of generate-id().
>
> <xsl:for-each select="SEC">
>  <a href="#{generate-id()}">

Hi Nick,

you only must find the way or XPath from SEC to T. Write this XPath in 
the paranthesis: generate-id(any/valid/XPath).

Regards,

Joerg

>   <xsl:value-of select="."/>
>  </a>
>  <xsl:text/>
>      <xsl:value-of select="following-sibling::*[1]"/><br/>
> </xsl:for-each>
> </xsl:template>
>
> <xsl:template match="T">
>      <a name="{generate-id()}"><xsl:value-of select="."/></a><br/>
> </xsl:template>
>
> Thanks
> Nick


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