Re: [xsl] linkdiff template

Subject: Re: [xsl] linkdiff template
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Thu, 13 Jun 2002 06:55:03 +0200
A key in XSLT is always created for every XML-tree. So you don't need a document() in the key's use-attribute. With your declaration the key of the indexed links is always the value of the first a/@href in $previous.

<xsl:key name="links" match="a" use="@href"/>

<xsl:param name="previous"/>

<xsl:template match="a">
  <xsl:variable name="href" select="@href"/>
  <xsl:for-each select="$previous">
    <xsl:if test="not(key('links', $href))">
      <xsl:value-of select="$href"/>
    </xsl:if>
  </xsl:for-each>
</xsl:template>

Regards,

Joerg

Guy McArthur wrote:
Hi, I'm looking to write a template to output the a/@href's from one (newer) file that are *not* present in another (older) file.

I.e. given the following two files
-old.xml-
<html>
 <a href="http://www.google.com/>Google!</a>
 <a href="http://w3.org/";>W3C</a>
</html>
-new.xml-
<html>
 <a href="http://w3.org/";>W3C</a>
 <a href="http://guymcarthur.com";>My HomePage</a>
 <a href="http://xml.apache.org/xalan/";>Xalan</a>
</html>
--
The output would be:
http://guymcarthur.com
http://xml.apache.org/xalan/

Here's my first stab at the stylesheet:
-linkdiff.xsl-
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:param name="previous"/>

<xsl:key name="links" match="a" use="document($previous)///a/@href"/>
<xsl:output method="text"/>


 <xsl:template match="a">
   <xsl:if test="not(boolean(key('links', @href)))">
     <xsl:value-of select="@href"/>
   </xsl:if>
 </xsl:template>

</xsl:stylesheet> --

However, it is just outputting all the href's (test is always true).
Please enlighten me!

I'm using 'java org.apache.xalan.xslt.Process -IN new.xml -XSL \
linkdiff.xsl -PARAM previous old.xml'.

GKM


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