Subject: Re: [xsl] basic xpath question From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Thu, 20 Jun 2002 10:32:27 +0100 |
Hi Dominic, > I have an xml document to be styled, if I have a construct such as > > <section id="para">this is text <section id="url" > url="http://xx.yy.zz">which is to be a link</section></section> > > How do I, in xslt, recognise the "url" tag within the "para" tag, > such that I could ouput someting like > > <p>this is test <a href="http://xx.yy.zz">which is to be a link</a></p> The simplest way would be to use templates that match section elements with different values for their id attributes: <xsl:template match="section[@id = 'para']"> <p><xsl:apply-templates /></p> </xsl:template> <xsl:template match="section[@id = 'url']"> <a href="{@url}"><xsl:apply-templates /></a> </xsl:template> Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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