Re: [xsl] XSLT output from XDR instead of XML

[Francis Norton <francis@xxxxxxxxxxx>]

Hi Perez,

Perez, Santiago wrote:

> Excuse the beginner question but has anyone ever tried building an XSLT data
> entry screen based on an XDR schema dynamically? I've been given the task to
> create a forms library from XDR Schemas
Sounds do-able provided you don't get too ambitious on scope. Things 
like repeating elements could be tricky. I'm not quite sure what you 
mean by "an XSLT data entry screen" - do you mean generating an HTML 
form with current field values supplied in an XML document, or do you 
mean  using XSLT to process the results of an HTML form into an XML 
document? Or something else again?

> I'm guessing I can do XSLT from the schema but not sure if I can bind XSLT
> to XDR instead of an XML.
No problem. An XDR (unlike a DTD) is XML. Also XDR is simpler than XSDL 
(the W3C XML schema language) but similar to it so you should be able to 
adapt examples that process XSDL.

> The problem is that I will not know what the node
> names will be in the XDR file ahead of time and therefore would have to
> create the XSL in such a way that it will not need the literal names of the
> nodes. Is there a way to do that?
Well, you know what the names of the XDR schema elements will be (eg 
"Element"), so that's what you match in your XSLT. You can get the names 
of the instance elements from the schema, and then include those in the 
XSLT.

> Any pointers or links or would be greatly appreciated. 
See TypeTagger at http://www.schemavalid.com/utils/typeTagger.zip for an 
example of XSLT that processes XSDL schemas in order to generate XSLT 
that processes instances of the schemas.

Francis.

--
"Never mind manoeuvre, go straight at 'em." - Admiral Horatio Nelson




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