Subject: Re: RE: [xsl] Forming a Tree From: "Venkatesh Sutrave" <vmsutrave@xxxxxxxxxxxxxx> Date: 12 Jul 2002 04:30:21 -0000 |
Thanks once again. Venkatesh
Where a stylesheet uses select="//x[@y=$z]", it can almost invariably be
speeded up significantly by using <xsl:key> and the key() function. Use
<xsl:key name="k" match="x" use="@y"/>
... select="key('k', $z)"
Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx
> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of
> Venkatesh Sutrave
> Sent: 11 July 2002 09:33
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Forming a Tree
>
>
> Hi,
> I am trying to form a tree on a raw XML, my input XML looks like
> -
>
> <?xml version="1.0"?>
> <Root>
> <row BookId="1" BookTitle="abc1" TopicId="1" ParentTopicId="1"
> TopicTitle="Topic1"/>
> <row BookId="1" BookTitle="abc1" TopicId="2" ParentTopicId="1"
> TopicTitle="Topic11"/>
> <row BookId="1" BookTitle="abc1" TopicId="4" ParentTopicId="4"
> TopicTitle="Topic12"/>
> <row BookId="1" BookTitle="abc1" TopicId="3" ParentTopicId="2"
> TopicTitle="Topic21"/>
>
> <row BookId="1" TopicId="1" SiteId="1" SortOrder="0"
> SiteTitle="Site1" />
> <row BookId="1" TopicId="2" SiteId="2" SortOrder="0"
> SiteTitle="Site2" />
> <row BookId="1" TopicId="3" SiteId="3" SortOrder="0"
> SiteTitle="Site3" />
> <row BookId="1" TopicId="4" SiteId="4" SortOrder="1"
> SiteTitle="Site4" />
> <row BookId="1" TopicId="4" SiteId="1" SortOrder="0"
> SiteTitle="Site1" />
> </Root>
>
> and my XSL is -
>
> <?xml version='1.0'?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <xsl:template match="Root">
> <TreeNodes>
> <xsl:apply-templates select="row[@BookTitle and
> not(preceding::row/@BookId=@BookId)]" />
> </TreeNodes>
> </xsl:template>
>
> <xsl:template match="row">
> <TreeNode>
> <xsl:variable name="node1" select="."/>
> <xsl:attribute name="BookId"><xsl:value-of
> select="@BookId"/></xsl:attribute>
> <xsl:attribute name="Text"><xsl:value-of
> select="@BookTitle"/></xsl:attribute>
>
> <!-- Topic node -->
> <xsl:for-each select="//row[@ParentTopicId=@TopicId and
> @BookId=$node1/@BookId and @TopicTitle]">
> <TreeNode>
> <xsl:variable name="node2" select="."/>
> <xsl:attribute name="TopicId"><xsl:value-of
> select="@TopicId"/></xsl:attribute>
> <xsl:attribute name="ParentTopicId"><xsl:value-of
> select="@ParentTopicId"/></xsl:attribute>
> <xsl:attribute name="Text"><xsl:value-of
> select="@TopicTitle"/></xsl:attribute>
>
> <!-- Sub-Topic1 -->
> <xsl:for-each
> select="//row[@ParentTopicId=$node2/@TopicId and
> @ParentTopicId!=@TopicId and @BookId=$node1/@BookId and
> @TopicTitle]">
> <TreeNode>
> <xsl:variable name="node3" select="."/>
> <xsl:attribute
> name="TopicId"><xsl:value-of select="@TopicId"/></xsl:attribute>
> <xsl:attribute
> name="ParentTopicId"><xsl:value-of
> select="@ParentTopicId"/></xsl:attribute>
> <xsl:attribute name="Text"><xsl:value-of
> select="@TopicTitle"/></xsl:attribute>
>
> <!-- Sub-Topic2 -->
> <xsl:for-each
> select="//row[@ParentTopicId=$node3/@TopicId and
> @ParentTopicId!=@TopicId and @BookId=$node1/@BookId and
> @TopicTitle]">
> <TreeNode>
> <xsl:variable name="node4"
> select="."/>
> <xsl:attribute
> name="TopicId"><xsl:value-of select="@TopicId"/></xsl:attribute>
> <xsl:attribute
> name="ParentTopicId"><xsl:value-of
> select="@ParentTopicId"/></xsl:attribute>
> <xsl:attribute
> name="Text"><xsl:value-of select="@TopicTitle"/></xsl:attribute>
>
> <!-- Site -->
> <xsl:for-each
> select="//row[@BookId=$node4/@BookId and @TopicId=$node4/@TopicId
> and @SiteId]">
> <xsl:sort select="@SortOrder"
> data-type="number"/>
> <TreeNode>
> <xsl:call-template
> name="SiteDetails">
> <xsl:with-param
> name="site" select="."/>
> </xsl:call-template>
> </TreeNode>
> </xsl:for-each>
> </TreeNode>
> </xsl:for-each>
>
> <!-- Site -->
> <xsl:for-each
> select="//row[@BookId=$node3/@BookId and @TopicId=$node3/@TopicId
> and @SiteId]">
> <xsl:sort select="@SortOrder"
> data-type="number"/>
> <TreeNode>
> <xsl:call-template
> name="SiteDetails">
> <xsl:with-param
> name="site" select="."/>
> </xsl:call-template>
> </TreeNode>
> </xsl:for-each>
> </TreeNode>
> </xsl:for-each>
>
> <!-- Site -->
> <xsl:for-each
> select="//row[@BookId=$node2/@BookId and @TopicId=$node2/@TopicId
> and @SiteId]">
> <xsl:sort select="@SortOrder"
> data-type="number"/>
> <TreeNode>
> <xsl:call-template name="SiteDetails">
> <xsl:with-param name="site"
> select="."/>
> </xsl:call-template>
> </TreeNode>
> </xsl:for-each>
> </TreeNode>
> </xsl:for-each>
> </TreeNode>
> </xsl:template>
>
> <xsl:template name="SiteDetails">
> <xsl:param name="site"/>
> <xsl:attribute name="TopicId"><xsl:value-of
> select="$site/@TopicId"/></xsl:attribute>
> <xsl:attribute name="SiteId"><xsl:value-of
> select="$site/@SiteId"/></xsl:attribute>
> <xsl:attribute name="Text"><xsl:value-of
> select="$site/@SiteTitle"/></xsl:attribute>
> </xsl:template>
>
> </xsl:stylesheet>
>
> I am applying transformation using .NET classes.
> Can the above XSL optimized to gain performance ?
> Can I avoid '//row' to achieve the same?
>
> Thanks in advance.
> Venkatesh _________________________________________________________
> There is always a better job for you at Monsterindia.com.
> Go now http://monsterindia.rediff.com/jobs
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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