Subject: RE: [xsl] wildcards in xpath? From: Stuart Brown <sbrown@xxxxxxxxxxxxx> Date: Wed, 24 Jul 2002 14:17:55 +0100 |
You'll have to use the general wildcard (*), and then filter this using a starts-with expression on the name() in the predicate, so: <xsl:for-each select="*[starts-with(name(),'dino')]"> Cheers, Stuart > -----Original Message----- > From: inchi2000@xxxxxx [mailto:inchi2000@xxxxxx] > Sent: 24 July 2002 14:12 > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] wildcards in xpath? > > > Hello, > > I have a short question to xpath. Is it possible to select > all nodes which > begin with "dino"? I want to do something like this: <xsl:for-each > select="dino*"> > But this didn't work. > > Markus > > P.S. Special Thanks to Jeni :) > > -- > GMX - Die Kommunikationsplattform im Internet. > http://www.gmx.net > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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