Subject: RE: [xsl] sort / unsort From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Fri, 9 Aug 2002 10:05:35 +0100 |
> Interesting, > Could you show me? I couldn't see a way of getting > a sorted nodeset into a variable. Wouldn't this approach require that? It needs the node-set() extension function. <xsl:variable name="n"> <xsl:for-each> <xsl:sort> <xsl:copy-of select="."/> </ </ <xsl:for-each select="xx:node-set($n)"> ... Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx > > -- Mike Berrow > > ----- Original Message ----- > From: "Mike Brown" <mike@xxxxxxxx> > To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> > Sent: Thursday, August 08, 2002 10:09 PM > Subject: Re: [xsl] sort / unsort > > > Mike Berrow wrote: > > Does anyone see a better way? > > I was going to try the Kay/Becker/Holman technique from the FAQ. > http://www.dpawson.co.uk/xsl/sect2/muench.html#d197e74 > > That is, find the difference between all the nodes and the > sorted nodes to get the remaining nodes. No need for > generate-id(); count() and != ought to work nicely. > > - Mike > ______________________________________________________________ > ______________ > mike j. brown | xml/xslt: http://skew.org/xml/ > denver/boulder, colorado, usa | resume: > http://skew.org/~mike/resume/ > > XSL-List info and archive: > http://www.mulberrytech.com/xsl/xsl-list > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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