Subject: [xsl] Re: xpath based on condition From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Wed, 14 Aug 2002 12:09:54 -0700 (PDT) |
Use: <xsl:variable name="xpath" select="//Header[$Path]/*[name()=$Path] | //Header[not($Path)]"/> Because the conditions in the two predicates negate each other, only one of the operands of the above union will actually be selected. Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL --- Joerg Heinicke <joerg dot heinicke at gmx dot de> wrote: > Hello Aruniima, > > you have to use <xsl:copy-of select="//Header/*[name()=$Path]"/>, but > with this you will create a Result Tree Fragment, which can be > converted back to a node set via an extension function. > > But maybe it's enough to use: > > <xsl:variable name="xpath-header" select="//Header"/> > > <xsl:variable name="xpath" select="$xpath-header/*[name()=$Path]"/> > > and do the logic whether to use $xpath-header or $xpath later. Maybe > you can also use > > <xsl:variable name="xpath" select="//Header/*[name()=$Path] | > //Header"/> > > (UNION of both node sets) and choose later the correct node/value > from > this node set. > > Regards, > > Joerg > > > > __________________________________________________ > Do You Yahoo!? > HotJobs - Search Thousands of New Jobs > http://www.hotjobs.com __________________________________________________ Do You Yahoo!? HotJobs - Search Thousands of New Jobs http://www.hotjobs.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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