Subject: Re: [xsl] document() function From: "Thomas B. Passin" <tpassin@xxxxxxxxxxxx> Date: Tue, 20 Aug 2002 15:51:38 -0400 |
[Felmey, Jonathan] > I am trying to do the following: > document('file:///c:/servers/mserver/ojamc2vpt1_part.xsd') to open a > document not in the same directory as my stylesheet. It does not work. Can > this be done and if so what is the correct syntax for doing this? > If you are trying this from within a browser, security restrictions would prevent it. Otherwise, it may be the syntax of the file: URL. Try some of the normal variations, like file:///c:\servers\mserver\ojamc2vpt1_part.xsd file:c:\servers\mserver\ojamc2vpt1_part.xsd file:c:/servers/mserver/ojamc2vpt1_part.xsd There is some ambiguity in the RFC about the exact form of file: URLs, leading to different interpretions, and different processors can require different forms. The form you used works on some processors, but I forget what works with which. Cheers, Tom P XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] document() function, Felmey, Jonathan | Thread | Re: [xsl] document() function, J.Pietschmann |
[xsl] document() function, Felmey, Jonathan | Date | Re: [xsl] document() function to ge, Mulberry Technologie |
Month |