Subject: Re: [xsl] getting distinct content from list (?) From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx> Date: Thu, 22 Aug 2002 15:36:59 +0000 |
From: Kurt George Gjerde <kurt.gjerde@xxxxxxxxxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: [xsl] getting distinct content from list (?) Date: Thu, 22 Aug 2002 16:31:10 +0200 (MET DST)
Hi,
The least of my xslt problems at the moment is this one (I have others which I'm sure I'll come back to ;). This is probably easy but I just can't see it. Here it goes.
I have an xpath which results in a list like: 'cynthia', 'bob', 'janet', 'bob', 'jack', 'bob', 'jack'.
These are user IDs collected from different locations in a document. The actual xpath is: notify/@user | /ming/users/user[@global-notify='yes']/@id | /ming/client[@id=$myClient]/admin/@user
I need to output this as: "bob, cynthia, jack and janet". Without the duplicates (sorted and xslt 1.0).
How?
Thanks, -Kurt. __________ kurt george gjerde <kurt.gjerde@xxxxxxxxxxxxxxxxx> intermedia uib, university of bergen
Free Jon - http://www.efn.no/freejon01-2002.html
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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