RE: [xsl] How to match a child element and display another child element?

["Américo Albuquerque" <aalbuquerque@xxxxxxxxxxxxxxxx>]

Hi.

try this:
<xsl:template match="FruitList">
 <xsl:apply-templates select="fruit[price='1' or price='1.0' or
price='1.00']/name"/> <!-- here is where you select the nodes that you
want to apply the templates to -->
</xsl:template>

<xsl:template match="name"> <!-- relative to your getName -->
 <xsl:value-of select="."/> is only $1.00.
</xsl:template>

hope that this helps you.

Americo.

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Biying Huang
Sent: Friday, August 23, 2002 1:43 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] How to match a child element and display another child
element?


When I am in FruitList node set, how can I display any one fruit name
that has price equals 1 (or 1.0 or 1.00)?  <xsl:template
match="FruitList">
    <xsl:call-template name="getName"/> is only $1.00.  </xsl:template>

<xsl:template name="getName">
  ??? I don't know how to do here, Please help.
</xsl:template>

I have this xml data:
<FruitList>
    <fruit>
        <name>Apple</name>
        <price>1.50</price>
    </fruit>
    <fruit>
        <name>Orange</name>
        <price>1.0</price>
    </fruit>
    <fruit>
        <name>Peach</name>
        <price>1</price>
    </fruit>
</FruitList>

Thanks in advance for your help.

Biying


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