Subject: RE: [xsl] Returning the file name of the input file From: Jarno.Elovirta@xxxxxxxxx Date: Wed, 28 Aug 2002 10:57:04 +0300 |
Hi, > Subject: [xsl] Returning the file name of the input file > > > Hello, > > does anybody if the following is possible: > > I want to use the name of the inputfile in the outputfile. So > if I want to > transform the file c:\temp\test.xml, I want to get in my output > c:\temp\test.xml. Pass the input filename as a parameter. Jarno XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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