Subject: RE: [xsl] Returning the file name of the input file From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Wed, 28 Aug 2002 09:23:11 +0100 |
> > does anybody if the following is possible: > > I want to use the name of the inputfile in the outputfile. So > if I want to transform the file c:\temp\test.xml, I want to > get in my output c:\temp\test.xml. I am afraid there is no > method to do this, but if anybody knows a solution I will be > very thankfull for that. > Of course this is possible, but the logic belongs in the script that you use to drive the XSLT transformation, not in the stylesheet itself. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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