Re: [xsl] how to zap content between sibling elements?

["Helder da Rocha" <helder@xxxxxxxxxxxxxxxx>]

Jay,

To get rid of the text between <k>s you need a XPath expression like:

    following-sibling::k and not(preceding-sibling::k)

in the context of the <p> element for the text before, and another one,
reversed for the text after. The code below solves the problem you posted:

    <xsl:template match="p">
        <p><xsl:copy-of select="*[not(self::k)]" />
        <xsl:apply-templates select="child::text()[following-sibling::k and
not(preceding-sibling::k)]" />
        <grp><xsl:apply-templates select="k" /></grp>
        <xsl:value-of select="following-sibling::text()" />
        <xsl:apply-templates select="child::text()[preceding-sibling::k and
not(following-sibling::k)]" /></p>
    </xsl:template>

    <xsl:template match="k">
        <k><xsl:apply-templates /></k>
    </xsl:template>

Helder.

--
Helder da Rocha (helder@xxxxxxxxxxxxxxxx)
Web Consultant
www.argonavis.com.br
São Paulo, Brazil
+55 (11) 9291 0567

----- Original Message -----
From: "Jay Han" <hjhjjj@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Wednesday, August 28, 2002 3:01 PM
Subject: [xsl] how to zap content between sibling elements?


> Hello all,
>
> I have a few siblings that I need to group together like this:
>
> original:
> <p> <!-- maybe some other element other than 'k' -->
> foo
>    <k>A</k> bar <k>B</k> baz <k>C</k>
> quux and more stuff
> </p>
>
> goal:
> <p>
> foo
>    <grp><k>A</k><k>B</k><k>C</k></grp>
> quux and more stuff
> </p>
>
> I can do the grouping  but I am having difficulties zapping 'bar'
> and 'baz' between <k>'s.  Currently I get:
> <p>
> foo
>    <grp><k>A</k><k>B</k><k>C</k></grp> bar baz
> quux and more stuff
> </p>
> I think I need a condition to my default copying template
> to handle the case of "when in-between <k>'s zap the content".
> What combination of axes and predicates can I use to express
> this condition?  Any hint or suggestion would be appreciated.
>
> thanks,
>
> -jay
>
>
> =====
> jhan@xxxxxxx
>
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