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Re: [xsl] Getting the XPath of a node

Subject: Re: [xsl] Getting the XPath of a node
From: Peter Davis <pdavis152@xxxxxxxxx> (by way of Peter Davis <pdavis152@xxxxxxxxx>)
Date: Wed, 4 Sep 2002 02:46:23 -0700
On Wednesday 04 September 2002 02:44, you wrote:
> reverse document order

I'm an idiot, please ignore that.  You can use <xsl:for-each
select="ancestor-or-self::*>, as Mike Brown said, instead of my stupid
recursive template.

--
Peter Davis


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