Subject: Re: [xsl] Siblings to hierarchy: Better way to do this? From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Fri, 06 Sep 2002 13:05:00 -0400 |
Also: I don't understand why this didn't work: if anyone can explain, I'd be grateful:
<xsl:apply-templates select="following-sibling::paragraph[preceding-sibling::section[1]=$sect]"/>
Enjoy, Wendell
Dear All,
I need to transform stuff in this form:
<r> <section/> <paragraph>adolf</paragraph> <paragraph>alex</paragraph> <section/> <paragraph>bertram</paragraph> <paragraph>bilbo</paragraph> <paragraph>bumble</paragraph> <section/> <paragraph>claus</paragraph> <paragraph>charles</paragraph> <paragraph>cymbaline</paragraph> </r>
to this:
<r> <section> <Para>adolf</Para> <Para>alex</Para> </section> <section> <Para>bertram</Para> <Para>bilbo</Para> <Para>bumble</Para> </section> <section> <Para>claus</Para> <Para>charles</Para> <Para>cymbaline</Para> </section> </r>
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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